I've got to admit, the 2nd trial was very tough. I didn't really anticipated the tricky questions they asked in Science and Maths. They really made me panicked during the test. Yesterday, I sat for BM and Moral test. BM was hard, but Moral was even harder. Sigh... it's confirmed that I will get a B in BM. I'm not trying to be negative here, it's true. I have 6 mistakes in my BM Paper 1 already. The BM and BI test in the 2nd trial uses the marks for Paper 2 in the 1st trial. Since I did quite badly for the first trial for BM, I have very small margin of error for the 2nd trial.
See, the first trial for BM, I've got 70/100 for Paper 2, or if you wanna follow my BM Teacher's calculations, 42%. How did he get 42 % from Paper 2?
70/100*60%=42% (Because Paper 2 is 60% of the whole BM test)
The 70 marks/42% for my first BM Paper 2 trial will be used in the 2nd trial.
If you use the normal way of counting BM Marks:
Total Marks=(P1+P2)/140*100
To get an A, I'll need at least 75%:
75=(P1+70)/140*100
P1=35
Work it out and you'll know that I must get at least 35 correct answers to get an A.
But if you follow my BM Teacher's calculation:
Total Marks=P1+(P2/100*60)
75=P1+(P2/100*60)
75=P1+42
P1=33
I've got a bigger margin of error. Obviously, I should use my BM Teacher's way of counting to get a bonus, even though his way is technically wrong, in a way. Why? Okay, here's why:
My BM Teacher assumes that BM Paper 2 makes up 60% of the whole BM test. So, 60% from P2 and 40% from P1 makes 100%. But this is wrong.
BM Paper 2 has a maximum score of 100. The total score of the whole BM Test is 140 (100 from P2, 40 from P1). So, the percentage of P2 from the whole test is:
P2=100/140*100
P2=(approx) 71.4
Yeah, so Paper 2 makes up about 71.4 % of the whole test. Now, you can see there's about 10% difference from my BM Teacher's 60%.
His formula should have been like this:
Total Marks=P1/40*28.6 + P2/100*71.4
This mistake in the calculation can cause some people to have a higher or lower mark than they are supposed to have. The proof is shown in a moment...
Now, the difference in the correct way of counting and my BM Teacher's way of counting can be seen in the equation below:
d=P1/40*28.6 + P2/100*71.4 - ( P1+(P2/100*60) )
Crank it, and you'll get:
d=11.4( (2 P2 - 5 P1)/200 )
Using my marks:
d=11.4( (2 x 70 - 5 x 29)/200 )
d= -0.285
We can make another formula:
R=W+d
where R=the score using the correct way of counting
W=the score using the wrong way of counting
So, using what I have:
R=71+(-0.285)
R=70.715
So, you can clearly see that I have a bonus of 0.285% in my marks, which isn't very incredible.
But, let's say you have 30 for Paper 1 and 80 for Paper 2,
W=30+80/100*60
W=78
d=11.4( (2 x 80 - 5 x 30)/200 )
d=0.57
R=W+d
R=78+0.57
R=78.57
R=(approx)79%
So, the real score is 79, but through the flawed way of calculation, you'll get 78. That's 1 mark less. The worst thing is, that mark will be the mark for BM, despite losing 1 mark. So, people, use the normal way of counting your BM mark.
As a conclusion to the formula I made up above, if you still rely on the flawed calculation method, you can determine if you gain or lose marks from the real not-flawed way of counting by using this:
if 2 x Paper 2 marks > 5 x Paper 1 marks, 2 P2>5 P1, you lose marks, so, use the correct way of counting your BM marks
if 2 x Paper 2 marks < 5 x Paper 1 marks, 2 P2<5 P1, you gain marks, so, use the flawed way to earn some marks.
But, you must ask your teacher first. If the teacher uses the wrong way of counting, then show his/her the proof.
First, count your marks using both of these formula:
A=(P1+P2)/140*100
B=P1 + P2/100*60
Compare both A and B. If A > B, you gain marks by telling his/her the right way of counting BM Marks. However, if B > A, just stick to his/her way of counting. If A=B, then do nothing. A will B if 5 x P1 = 2 x P2.
And, I've finally finished Proud Mode of Kingdom Hearts Chain of Memories! I kicked Marluxia's ass like mad!! A very good way of releasing stress!!
See, the first trial for BM, I've got 70/100 for Paper 2, or if you wanna follow my BM Teacher's calculations, 42%. How did he get 42 % from Paper 2?
70/100*60%=42% (Because Paper 2 is 60% of the whole BM test)
The 70 marks/42% for my first BM Paper 2 trial will be used in the 2nd trial.
If you use the normal way of counting BM Marks:
Total Marks=(P1+P2)/140*100
To get an A, I'll need at least 75%:
75=(P1+70)/140*100
P1=35
Work it out and you'll know that I must get at least 35 correct answers to get an A.
But if you follow my BM Teacher's calculation:
Total Marks=P1+(P2/100*60)
75=P1+(P2/100*60)
75=P1+42
P1=33
I've got a bigger margin of error. Obviously, I should use my BM Teacher's way of counting to get a bonus, even though his way is technically wrong, in a way. Why? Okay, here's why:
My BM Teacher assumes that BM Paper 2 makes up 60% of the whole BM test. So, 60% from P2 and 40% from P1 makes 100%. But this is wrong.
BM Paper 2 has a maximum score of 100. The total score of the whole BM Test is 140 (100 from P2, 40 from P1). So, the percentage of P2 from the whole test is:
P2=100/140*100
P2=(approx) 71.4
Yeah, so Paper 2 makes up about 71.4 % of the whole test. Now, you can see there's about 10% difference from my BM Teacher's 60%.
His formula should have been like this:
Total Marks=P1/40*28.6 + P2/100*71.4
This mistake in the calculation can cause some people to have a higher or lower mark than they are supposed to have. The proof is shown in a moment...
Now, the difference in the correct way of counting and my BM Teacher's way of counting can be seen in the equation below:
d=P1/40*28.6 + P2/100*71.4 - ( P1+(P2/100*60) )
Crank it, and you'll get:
d=11.4( (2 P2 - 5 P1)/200 )
Using my marks:
d=11.4( (2 x 70 - 5 x 29)/200 )
d= -0.285
We can make another formula:
R=W+d
where R=the score using the correct way of counting
W=the score using the wrong way of counting
So, using what I have:
R=71+(-0.285)
R=70.715
So, you can clearly see that I have a bonus of 0.285% in my marks, which isn't very incredible.
But, let's say you have 30 for Paper 1 and 80 for Paper 2,
W=30+80/100*60
W=78
d=11.4( (2 x 80 - 5 x 30)/200 )
d=0.57
R=W+d
R=78+0.57
R=78.57
R=(approx)79%
So, the real score is 79, but through the flawed way of calculation, you'll get 78. That's 1 mark less. The worst thing is, that mark will be the mark for BM, despite losing 1 mark. So, people, use the normal way of counting your BM mark.
As a conclusion to the formula I made up above, if you still rely on the flawed calculation method, you can determine if you gain or lose marks from the real not-flawed way of counting by using this:
if 2 x Paper 2 marks > 5 x Paper 1 marks, 2 P2>5 P1, you lose marks, so, use the correct way of counting your BM marks
if 2 x Paper 2 marks < 5 x Paper 1 marks, 2 P2<5 P1, you gain marks, so, use the flawed way to earn some marks.
But, you must ask your teacher first. If the teacher uses the wrong way of counting, then show his/her the proof.
First, count your marks using both of these formula:
A=(P1+P2)/140*100
B=P1 + P2/100*60
Compare both A and B. If A > B, you gain marks by telling his/her the right way of counting BM Marks. However, if B > A, just stick to his/her way of counting. If A=B, then do nothing. A will B if 5 x P1 = 2 x P2.
And, I've finally finished Proud Mode of Kingdom Hearts Chain of Memories! I kicked Marluxia's ass like mad!! A very good way of releasing stress!!
0 comments:
Post a Comment